Find unknown wind velocity given airlplane's speed

  • Thread starter Thread starter Gardunf070
  • Start date Start date
  • Tags Tags
    Vector
AI Thread Summary
The discussion centers on calculating wind velocity based on an airplane's airspeed and its observed ground speed. The airplane flies at 50.0 m/s towards E40°N, while an observer on the ground measures its speed as 30.0 m/s towards S45°E. The calculated wind velocity is 56 m/s directed W72°S, which confuses some participants since both vectors appear to point east. Clarification is provided that the wind's direction indicates it is blowing from the NE to the SW, affecting the airplane's trajectory. Ultimately, the airplane's apparent movement is due to the combined effects of its speed and the wind's influence.
Gardunf070
Messages
1
Reaction score
0
Member warned that some effort must be shown in homework problems.
Homework Statement
An aeroplane flies with an airspeed of 50.0 m/s [E40°N]. If the velocity of the plane, according to an observer on the ground, is 30.0 m/s [S45°E], what is the wind velocity?
Relevant Equations
Here is the answer:
The wind velocity is 56 m/s [W72°S]
But I don't understand how is that it ends up on the west side if both vectors were pointing east.
 
Physics news on Phys.org
:welcome:

So what is  your answer for the wind speed?
 
Gardunf070 said:
Homework Statement: An aeroplane flies with an airspeed of 50.0 m/s [E40°N]. If the velocity of the plane, according to an observer on the ground, is 30.0 m/s [S45°E], what is the wind velocity?
Relevant Equations: Here is the answer:
The wind velocity is 56 m/s [W72°S]

But I don't understand how is that it ends up on the west side if both vectors were pointing east.
Which two vectors add to make the third?
 
Gardunf070 said:
Here is the answer:
The wind velocity is 56 m/s [W72°S]

But I don't understand how is that it ends up on the west side if both vectors were pointing east.
Welcome, @Gardunf070 !

What do you believe ends up on the West side?

W72°S is only the direction towards which the wind is blowing.
The observer on the ground feels that the wind is moving from the NE to the SW quadrant.

Not being able to see the ground as a reference, but only his instruments, the pilot believes that the airplane is moving from the SW to the NE quadrant at 50 m/s.

Simultaneously, that observer on the ground believes that the plane is moving from the NW to the SE quadrant at 30.0 m/s, although strangely, its nose points approximately towards the NE (the airplane is "crabbing").

1Ckx87.gif
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top