Kinematics motion - Dancers pausing at top of their leap

[TSny]

Show the steps you used so we can identify your mistake.

 

[negation]

show the steps you used so we can identify your mistake.

 

[TSny]

Good until the last line. How would you simplify $\frac{h}{\sqrt{h}}$?

 

[negation]

Good until the last line. How would you simplify $\frac{h}{\sqrt{h}}$?

h.h^-0.5

 

[negation]

Good until the last line. How would you simplify $\frac{h}{\sqrt{h}}$?

above

 

[TSny]

Can you simplify $h\cdot h^{-1/2}$?

 

[negation]

Can you simplify $h\;h^{-1/2}$?

equals h^(0.5)
sqrt(h)

This is it.

 

[TSny]

Good. So you have shown
$\frac{h}{\sqrt{-gh}} = \frac{h}{\sqrt{-g}\;\sqrt{h}} = \frac{h}{\sqrt{-g}\;h^{1/2}} = \frac{\sqrt{h}}{\sqrt{-g}}= \sqrt{-\frac{h}{g}}$

 

[TSny]

So, you have now found the time to go from 0 to h and also the time to go from h/2 to h.

 

[negation]

So, you have now found the time to go from 0 to h and also the time to go from h/2 to h.

So it's just basic division and cancellation left.

 

[TSny]

Yes.

 

[negation]

Yes.

I'll finish it up and post it. Thanks!

 

[TSny]

OK. I will check tomorrow. Cheers!

 

[negation]

Answer is 70.7%

 

[TSny]

Yes, that's the right answer.