Magnitude of tension force using moment

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The discussion centers on calculating the tension force in three cables lifting a uniform steel ring weighing 600 lbs. The initial attempt suggested that two cables would have a tension of 250 lbs each, while the third cable would have 100 lbs, based on an assumption of equal angles. However, the contributor expresses uncertainty about the setup, particularly regarding the attachment points and angles of the cables. The challenge lies in accurately determining the tension in each cable rather than a single tension value, as the situation involves minimal acceleration aside from gravity. Clarification on the attachment points and angles is needed to proceed with the calculations effectively.
kleeds
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Homework Statement


a uniform steel ring 60" in diameter and weighing 600 lbs is lifted by three cables each 50" long attached at points A (90*) B (90*) C (120*) with a radius of 30". compute the magnitude of tension force in each cable

Homework Equations


all moment equations
ft=ma

The Attempt at a Solution


first two cables have a force of 250 lbs and last one has 100 lbs. more of an incorrect guess figured since two have the same angle they would be the same. since there is almost no acceleration (besides gravity) i don't think i could solve it with my equation. it also wouldn't help because i need tension in each string not one tension.

note: degrees=*
 
Last edited:
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welcome to pf!

hi kleeds! welcome to pf! :smile:

kleeds said:
a uniform steel ring 60" in diameter and weighing 600 lbs is lifted by three cables each 50" long attached at points A (90*) B (90*) C (120*) with a radius of 30". compute the magnitude of tension force in each cable

i don't understand what the tops or bottoms of the cables are attached to, or what those angles are :confused:
 

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