- #141
Bob_for_short
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meopemuk said:Once you got the Hamiltonian H, finding solutions for wave functions is just a technical task. ...
Thank you, Eugene, for your answer. But let Strangerep and DarMM answer. Maybe they will write something specific for the problem solution.
As I said previously, apart from equations, there are also some "boundary" conditions that fix the linear superposition coefficients. I know the spectrum of operators A. I want the problem solution in terms of As and their vacuums. How many A-quanta are present in the solution, what is the average energy, etc.? I need an explicit solution to calculate all that. A formula like the original one for Ψ but in terms of A and their vacuums. Isn't it the formula given in my post #110? Anyway, I am very sure that our rigorous mathematicians can find and write this problem solution.
The exact solution in terms of a-operators does not contain any interaction between different a-modes either. They remain decoupled....In this particular case the solution is trivial: The Hamiltonian (in terms of physical a/c operators) has a non-interacting form, so physical particles propagate free, without interactions.
I consider the a-operators as physical. They carry energy-momentum, spin, etc., as dictated by their antenna j(r,t) You all blame them for nothing, in my opinion.In the general case, it is a much more complicated task to express physical states as linear combinations of "bare" states. But, as I stressed a few times already, such expressions have no physical meaning, so we should not bother.
But let us wait for the answer.
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