Sliding mass on sliding incline

Click For Summary
A block of mass m slides down a frictionless incline on a triangular block of mass M, which is also free to slide on a horizontal plane. The user is seeking confirmation on their calculations for the horizontal force and the resulting acceleration of mass M. A key point raised in the discussion is whether the accelerations of both blocks are the same and the importance of considering their directional relationship. The solution requires careful consideration of the forces acting on both masses and their respective accelerations. Understanding the interaction between the two masses is crucial for solving the problem accurately.
zheng89120
Messages
139
Reaction score
0

Homework Statement



A block of mass m slides down the incline of a triangular block of mass M. The angle of inclination is \theta. The trianguilar block is free to slide on a horizontal plane. Assume that all surfaces are frictionless. What is the acceleration of the mass M?

Homework Equations



F(net)=ma=0

The Attempt at a Solution



so basically i want to ask if my answer is correct, as I'm not familiar with this type of problem, i got:

F(horizontal) = mg cos \theta sin \theta
a(M, horizontal) = F(horizontal) / (m + M)

is this right?
 
Last edited:
Physics news on Phys.org
zheng89120 said:

Homework Statement



A block of mass m slides down the incline of a triangular block of mass M. The angle of inclination is \theta. The trianguilar block is free to slide on a horizontal plane. Assume that all surfaces are frictionless. What is the acceleration of the mass M?

Homework Equations



F(net)=ma=0

The Attempt at a Solution



so basically i want to ask if my answer is correct, as I'm not familiar with this type of problem, i got:

F(horizontal) = mg cos \theta sin \theta
a(M, horizontal) = F(horizontal) / (m + M)

is this right?
Not quite. Are the accelerations of the 2 blocks the same? What about the direction of the accelerations?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 27 ·
Replies
27
Views
10K
Replies
4
Views
3K
Replies
12
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K