- #421
consciousness
- 131
- 13
zoobyshoe said:I don't understand. Isn't the goal to end up with one ball at each separate end?
Yes, this is the first step towards that goal. Second step is same as in Enigman's solution.
zoobyshoe said:I don't understand. Isn't the goal to end up with one ball at each separate end?
Enigman said:You don't have to spoiler everything...
No, conciousness' method would not work ifthe axis passes through the end of tube but if if the axis is somewhere between the center of mass of the spheres it would get the job done.
I reworded the question slightly removing the emphasis on "job." suffice it to say the masked man is at his occupation at the time.collinsmark said:A man is running home, but he's afraid to get there, because there is another man already there who is wearing a mask."
What is the masked man's occupation?
zoobyshoe said:People are watching the masked man?
Office_Shredder said:On the masked man:
The two men are married (hence the diamond). The job the man at home is doing is that he does webcam shows for money and wears a mask while doing them - the man returning home was surfing online for pornography while at work and found his husband doing these shows, and is running home to confront him in the act.
It's a reach but I figured I'd post it.
zoobyshoe said:Edit:We don't know the diameter of the cylinder. It could be large enough that both balls can rest against an end circle side by side in a line perpendicular to the length of the pipe.More specifically, we don't know the inside diameter of the cylinder. That makes knowing the ball dimensions moot.
Enigman said:Any ideas about collinsmark's puzzle? Last time I was this lost was the chinese forensics enigma...darned baseball...
Where is that occam's razor when you need it?
zoobyshoe said:Mask:
"Home" is home plate in the game of baseball. The man with the mask he fears is the catcher: is someone throws the catcher the ball before the man get's "home" the man will be "out". Baseball is played on a "diamond".
Enigman said:A monk climbs to the top of a certain mountain with unequal speeds and random stops of random durations, he reaches the top at the sunset of the 13th day from the start. After meditating there for a week, he starts climbing down the mountain at the sunrise with unequal speeds and random stops. The speed while climbing down is obviously greater than speed climbing up. Assuming that he follows the exact same path for both journeys prove that there exists a time of day where the monk was at the same position on the path for both journeys.
So, "time of day" could be as vague as "morning," "afternoon," or "night"?Enigman said:The time of day can be any thing...
The monk only travels during daylight hours, then?Enigman said:Time of day could belong to the whole range of 6:00 am to 6:00 pm* and would be determined how the monk decides to carry out his journeys.**
*assuming sunrise and sunset at those times.
Both trips have to start at sunrise and end at sunset?Enigman said:...all that is of significance is both the trips start and end at the same time of day/night...
There's nothing to indicate the first journey was started at the same time of day the second was.A monk climbs to the top of a certain mountain with unequal speeds and random stops of random durations, he reaches the top at the sunset of the 13th day from the start. After meditating there for a week, he starts climbing down the mountain at the sunrise with unequal speeds and random stops. The speed while climbing down is obviously greater than speed climbing up. Assuming that he follows the exact same path for both journeys prove that there exists a time of day where the monk was at the same position on the path for both journeys.
You specify that he starts the first trip at sunrise and reaches the top at sunset. You also specify that he starts the second trip at sunrise, but there is no destination time given for this return trip. Is the time he finishes the second trip immaterial?Enigman said:oops...sorry.
Okay rephrasing the question:
A monk climbs to the top of a certain mountain starting at sun-rise with unequal speeds and random stops of random durations, he reaches the top at the sunset of the same day. After meditating there for a week, he starts climbing down the mountain at the sun-rise with unequal speeds and random stops. Assuming that he follows the exact same path for both journeys prove that there exists a time of day where the monk was at the same position on the path for both journeys.
Gad said:On about 1/3 of the path on the way up?
Enigman said:Think of the two trips simultaneously...
zoobyshoe said:Imagine a straight line segment with a dot at both ends. The line represents the mountain path, the dots represent the monk on his two different trips. The dots simultaneously start to move to the other end from where they started. Their respective motions can be smooth or erratic, fast or slow, but there must, inevitably, be a point where they meet and pass each other. That point is "the same time of day for both journeys."