Solve Enjoyable Enigmas with Mr.E's Challenge

  • Thread starter Enigman
  • Start date
In summary: Four princes approach the king vying for the hand of the princess. In order to choose the best among the four suitors the king and the princess arrange a test: the suitors are brought to a large rectangular hall. The floor is covered with a carpet all over except at the corners- where there are four squares of bare floor and the suitors are told to stand at these corner. Each suitor takes a corner and stands there while the princess stands at the center of the hall. The king then proclaims the prince who without leaving their respective squares shall put a ring on the princess's hand will be declared to be the bridegroom of his daughter and the heir to Enigmania. No ropes or rods are
  • #386
jhae2.718 said:
Either I'm misunderstanding the question, or aren't there many solutions? (159, 478, 263)
and (259, 173, 468), for example, are both solutions they way I am reading the problem.
You are correct! I've re-written the problem to reflect the fact there is more than only one right answer.
 
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  • #387
jhae2.718 said:
Square = 6, Triangle = 3, Circle = 2
Correct!
 
  • #388
The tennis balls:
1
 
  • #389
zoobyshoe said:
You are standing on a hard concrete floor and you have no cushioning to use. You bet someone you can drop a raw egg 4 feet without it breaking. You promise you won't even drop it on your feet. How do you win this bet?

Take your shoe off, put the egg inside, and drop it four feet.
 
  • #390
You bet someone you can drop a raw egg 4 feet without it breaking.
You can fulfill this pretty easily without moving or catching the egg, or magic or special effects, by simply taking advantage of something you haven't promised.
 
  • #391
jhae2.718 said:
Take your shoe off, put the egg inside, and drop it four feet.
Try it. If it works, I accept it as correct. Hehe.
 
  • #392
Egg drop:

Drop an egg that's already broken?
 
  • #393
... define raw egg, Zshoe?
 
  • #394
jhae2.718 said:
Egg drop:

Drop an egg that's already broken?
Hmmm...no.
 
  • #395
Gad said:
... define raw egg, Zshoe?
Uncooked in any way. You are claiming you can drop it 4 feet without the shell or even the yolk breaking.
 
  • #396
zoobyshoe said:
Uncooked in any way. You are claiming you can drop it 4 feet without the shell or even the yolk breaking.

drop it from 5 feet, and catch it with your hand before it touches the ground? :b
 
  • #397
Another solution for raw egg (I think is the one zooby was getting at) -
Lift the egg to more than four feet and drop it. The egg will break but it will fall 4 feet without breaking! Fulfilling all the parameters in the problem!
 
  • #398
consciousness said:
another solution for raw egg (i think is the one zooby was getting at) -
lift the egg to more than four feet and drop it. The egg will break but it will fall 4 feet without breaking! Fulfilling all the parameters in the problem!
Bingo!
 
  • #399
Well, that's technically my answer, even if my try to catch it failed, it already passed the four feet safely, right Zshoe? :biggrin:
 
  • #400
Gad said:
Well, that's technically my answer, even if my try to catch it failed, it already passed the four feet safely, right Zshoe? :biggrin:
Enigman already suggested your answer, though.
 
  • #401
zoobyshoe said:
Suppose you coat a tennis ball with glue. What is the maximum number of tennis balls that can be attached directly to this sticky surface?

This is another way of asking "What is the coordination number/ligancy in a FCC/HCP lattice? The answer is 12.
 
  • #402
consciousness said:
This is another way of asking "What is the coordination number/ligancy in a FCC/HCP lattice? The answer is 12.
I don't know what you just said, but, yes, the correct answer is 12. Office Shredder would have been correct but he decided to put his money on the answer being a perverse case where you deform things and fit 13 in.
 
  • #403
He was talking about atomic crystal packing, FCC or face-centred cubic arrangement of atoms is the most efficient packing of them all. Alternatively called H.C.P.- hexagonal close packing. Another honourable mention would be the kissing number problem of which your enigma is a special case of (the 3-d case). http://en.wikipedia.org/wiki/Kissing_number_problem
 
  • #404
This one should be a quickie-
You are given two plastic cups taped together at the rim- making a closed cylinder of sorts, inside it there are two table tennis balls. Your goal is to get the balls at opposite end of the cups. You are not allowed to break or untape anything.
 
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  • #405
Enigman said:
This one should be a quickie-
You are given two plastic cups taped together at the rim- making a closed cylinder of sorts, inside it there are two table tennis balls. Your goal is to get the balls at opposite end of the cups. You are not allowed to break or untape anything.

Rotate the cylinder w.r.t. to symmetric axis
 
  • #406
Correct. (Nitpicking: there are two symmetrical axis)
 
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  • #407
zoobyshoe said:
I don't know what you just said, but, yes, the correct answer is 12. Office Shredder would have been correct but he decided to put his money on the answer being a perverse case where you deform things and fit 13 in.

One of the reasons that 13 was considered a legitimate possibility is that if you take fourteen oranges, and put one in the middle, you can squeeze thirteen of them to all be adjacent to that orange at the same time. If you had asked for billiard balls or something the answer would be 12, but I think tennis balls are squishy enough that the correct answer should be 13.
 
  • #408
A monk climbs to the top of a certain mountain with unequal speeds and random stops of random durations, he reaches the top at the sunset of the 13th day from the start. After meditating there for a week, he starts climbing down the mountain at the sunrise with unequal speeds and random stops. The speed while climbing down is obviously greater than speed climbing up. Assuming that he follows the exact same path for both journeys prove that there exists a time of day where the monk was at the same position on the path for both journeys.
 
  • #409
I modified Enigman's question, making it slightly more difficult-

You have a long metal cylinder say 1 meter in length. It is known that there are 2 table tennis balls(of known dimensions) somewhere inside it. Devise a method to guarantee that the balls are put at opposite ends of the cylinder.
 
  • #410
Enigman said:
A monk climbs to the top of a certain mountain with unequal speeds and random stops of random durations, he reaches the top at the sunset of the 13th day from the start. After meditating there for a week, he starts climbing down the mountain at the sunrise with unequal speeds and random stops. The speed while climbing down is obviously greater than speed climbing up. Assuming that he follows the exact same path for both journeys prove that there exists a time of day where the monk was at the same position on the path for both journeys.

He was at the end of the path at 6 o clock for both journeys. :biggrin:
 
  • #411
For #409
1)hold the pipe vertically.
2)turn it over
3)1/2 - 2r=1/2 gt^2
4)(1-4r/g)^0.5=t
5)At t start spinning the tube in a horizontal plane like a mad man.( would work in vertical plane but you will have to spin harder)

For #410
No he wasn't. Position is with respect to the path. At 6:00 pm on first journey he was at top of mountain on second he was at the bottom of it.
No word play involved.
 
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  • #412
Enigman said:
For #409
1)hold the pipe vertically.
2)turn it over
3)1/2 - 2r=1/2 gt^2
4)(1-4r/g)^0.5=t
5)At t start spinning the tube in a horizontal plane like a mad man.( would work in vertical plane but you will have to spin harder)

Hehe that will undoubtedly work. But if you can do that you probably deserve an Olympic gymnastics medal for amazing timing and dexterity! :-p There is an easier method.

About monk-
I meant that he was on the path near the mountain at 6 o clock (sunset/sunrise), once while going and once while coming.

Edit: Okay you are distinguishing between AM and PM.
 
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  • #413
collinsmark said:
A man is running home, but he's afraid to get there, because there is another man already there who is wearing a mask and doing a "job."

What is the masked man's occupation?

Hint: there is a diamond involved.

zoobyshoe said:
I'm thinking it's a workman wearing a dust mask drilling into masonry with a diamond tipped drill.

No, that's not correct.*

Here's a hint though: people are watching him.

*[Edit: okay, so maybe it fits, but there's a better answer.]
 
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  • #414
consciousness said:
Hehe that will undoubtedly work. But if you can do that you probably deserve an Olympic gymnastics medal for amazing timing and dexterity! :-p There is an easier method.
hold the pipe vertically
slowly turn the pipe into a horizontal plane
start spinning with the axis at 2r
 
  • #415
collinsmark said:
Here's a hint though: people are watching him.
People are watching the masked man?
 
  • #416
On the masked man:
The two men are married (hence the diamond). The job the man at home is doing is that he does webcam shows for money and wears a mask while doing them - the man returning home was surfing online for pornography while at work and found his husband doing these shows, and is running home to confront him in the act.

It's a reach but I figured I'd post it.
 
  • #417
consciousness said:
I modified Enigman's question, making it slightly more difficult-

You have a long metal cylinder say 1 meter in length. It is known that there are 2 table tennis balls(of known dimensions) somewhere inside it. Devise a method to guarantee that the balls are put at opposite ends of the cylinder.
Float the cylinder in a tank of hot water without letting it rotate. The hot side should expand. The two ends will then be elevated and the balls should center themselves, one on each side of the mid line. Carefully rotate the cylinder 180 (on the axis that goes through the centers of the end circles). One ball should roll to one end and the other ball to the other end.
 
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  • #418
Enigman said:
hold the pipe vertically
slowly turn the pipe into a horizontal plane
start spinning with the axis at 2r

Yes correct. You can also-
Rotate with axis at an end to ensure that the balls collect at the other end.

zoobyshoe said:
Float the cylinder in a tank of hot water without letting it rotate. The hot side should expand. The two ends will then be elevated and the balls should center themselves, one on each side of the mid line. Carefully rotate the cylinder 180 (on the axis that goes through the centers of the end circles). One ball should roll to one end and the other ball to the other end.

That is a nice solution. There is a simpler solution similar to Enigman's original question's solution also.
 
  • #419
consciousness said:
Yes correct. You can also-
Rotate with axis at an end to ensure that the balls collect at the other end.
I don't understand. Isn't the goal to end up with one ball at each separate end?
 
  • #420
zoobyshoe said:
I don't understand. Isn't the goal to end up with one ball at each separate end?

You don't have to spoiler everything...
No, conciousness' method would not work if
the axis passes through the end of tube but if if the axis is somewhere between the center of mass of the spheres it would get the job done.
Now let's work on collinsmarks' diamond mask enigma...
Thinking out loud-
Man A
  1. Mask uses- hide identity/ protects the face/sports/decorational/medical/torture/religious
  2. Spectators (plural, more than one) watching whom? A, B or both?
  3. "Job"
  4. At home

Man B
  1. Afraid.
  2. Running towards home
  3. Not at home
  4. Afraid because A's doing a job
  5. Apostrophes around "job"
  6. Implies it would not usually be called job?
mmm...Obvious answer ruled out by A 2
Mention of diamond. Gem? With whom? A or B? Or shape? Rhombus? Playing cards?
I am drawing a serious blank...Anyone any ideas? I am certain the diamond is more of a misdirection than a hint, though the spectators thing should be a hint.
 

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