Speed C is Dependant Upon Source?

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  • #71
beatrix kiddo said:
i still disagree. i mean a photon is energy right?

No: A photon has energy. A photon is not to be identified with energy.

well if the energy isn't destroyed then the photon isn't destroyed.

The energy is not destroyed, but the photon is. It has to be in order for the atom to attain the higher energy state.

maybe stewarta is correct. maybe the photon gets stopped by the mirror and then the photon is accelerated at c, back off the mirror.

This cannot be, because EM fields (the only thing around that can possibly exert appreciable forces on things) do not interact with photons.
 
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  • #72
BobG said:
Makes sense as long as I stay on the surface. The photons being absorbed by atoms and then released adds some confusion factor.

But, when I think about it, it could be thought of as the photon's kinetic energy has been converted to potential energy when the electron level is raised. When the electron falls back into its original orbit, the potential is reconverted back to kinetic energy.

I take back the comment about thinking it made some sense.

If the satellite were massive and did not move, it would make sense. The light leaves with the same amount of energy it left with. The fact that the satellite does move due to solar pressure means some of the energy has been transferred to the satellite.

I'm having trouble figuring out how everything balances out.

Of course, the energy of light depends not upon its speed, which is constant, but upon its intensity and frequency. So, if the satellite moves away from the light source, the light reflected must be emitted at a lower frequency than it had when it first struck the surface.

Close?
 
  • #73
BobG said:
I take back the comment about thinking it made some sense.

If the satellite were massive and did not move, it would make sense. The light leaves with the same amount of energy it left with. The fact that the satellite does move due to solar pressure means some of the energy has been transferred to the satellite.

I'm having trouble figuring out how everything balances out.

Of course, the energy of light depends not upon its speed, which is constant, but upon its intensity and frequency. So, if the satellite moves away from the light source, the light reflected must be emitted at a lower frequency than it had when it first struck the surface.

Close?

Sounds right, the photoelectric effect and all that.
 
  • #74
BobG said:
If the satellite were massive and did not move, it would make sense. The light leaves with the same amount of energy it left with. The fact that the satellite does move due to solar pressure means some of the energy has been transferred to the satellite.

I'm having trouble figuring out how everything balances out.
Take a speed and reverse it, you get -v. Since the energy equation includes v^2, the minus signs cancel out and you get the exact same energy as you had before, but in the opposite direction.

Momentum, on the other hand, has just v...
 
  • #75
Doc Al said:
It's no different than bouncing a ball against a wall. The ball has incoming momentum +p. If it bounces back (like a superball), then it's final momentum will be -p, so [itex]\Delta p = -2p[/itex]. If it's absorbed (like a putty ball), then the final momentum is 0 (assume a massive wall) and [itex]\Delta p = -p[/itex]. The ball that bounces off transfers more momentum to the wall that the one that sticks.

The used to sell light pinwheels in novelty shops [still do, i suppose]. The 'clockwise' face of each vane is painted white, the opposing face is painted black. It is suspended in an evacuated glass container to eliminate air resistance. When exposed to bright light, the wheel spins clockwise.
 
  • #76
Chronos said:
The used to sell light pinwheels in novelty shops [still do, i suppose]. The 'clockwise' face of each vane is painted white, the opposing face is painted black. It is suspended in an evacuated glass container to eliminate air resistance. When exposed to bright light, the wheel spins clockwise.

These pinwheels actually work on heat differential, not solar pressure. It's virtually impossible (at least with today's technology) to test the effects of solar pressure on Earth. To come close, the evacuated glass container would have to be a perfect vacuum, vs. the extremely low pressure it actually is.

I'm not alone in trying to figure out how to correlate solar pressure with the idea that light will leave a 'perfect' mirror with the same energy it entered.

Thomas Gold (Center for Radiophysics and Space Research, Cornell University) has some doubts, as well.
http://www.arxiv.org/html/physics/0306050

I have some problems with his paper, though. The biggest is that satellites reportedly do experience a force from solar pressure. Solar pressure can cause torques which disturb satellite attitude and changes the eccentricity of geosynchronous satellites, given enough time.

Louis Friedman, working on the Cosmos I, a satellite which will use solar sail propulsion defends the idea that solar pressure does exert a force on satellites:
http://www.planetary.org/solarsail/ss_and_physics.html

I have some doubts about how well the experiment will work so close to Earth and even they realize the observed effects are likely to be very small. (Other effects, such as gravity gradients, tend to dwarf the effect of solar pressure for low orbiting satellites.

If solar pressure does exert a net force on a satellite, then there has to be energy conservation. The light has to lose some energy in transition. This letter comes closest to explaining how energy balances out:
http://solarsails.info/news/newscientistletter.html

Since the energy of light depends on its intensity and frequency, the light reflected off the mirror has to see a reduction in one or the other.
 
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  • #77
russ_watters said:
Take a speed and reverse it, you get -v. Since the energy equation includes v^2, the minus signs cancel out and you get the exact same energy as you had before, but in the opposite direction.

Momentum, on the other hand, has just v...

If you reduce v, don't you also reduce v^2?
 
  • #78
Chronos said:
The used to sell light pinwheels in novelty shops [still do, i suppose]. The 'clockwise' face of each vane is painted white, the opposing face is painted black. It is suspended in an evacuated glass container to eliminate air resistance. When exposed to bright light, the wheel spins clockwise.
That's a Crookes' Radiometer. It doesn't rotate because of the light hitting the vanes, though. It is chronically sold with that misinformation in accompanying literature. This site explains how it actually works:

Crookes radiometer
Address:http://www.fact-index.com/c/cr/crookes_radiometer.html
 
  • #79
zoobyshoe said:
That's a Crookes' Radiometer. It doesn't rotate because of the light hitting the vanes, though. It is chronically sold with that misinformation in accompanying literature.
Right! If light pressure were the cause of the vanes spinning, the vanes would spin in the opposite direction than they do.
 
  • #80
BobG said:
If you reduce v, don't you also reduce v^2?
Well sure - but who said anythign about reducing v? All you are changing is the sign. The magnitude stays the same.
 
  • #81
russ_watters said:
Well sure - but who said anythign about reducing v? All you are changing is the sign. The magnitude stays the same.

I guess I just missed what you were trying to say.

I agree that reflected light has to leave at the same speed it entered. But something has to change in order to account for motion caused by solar pressure. If a more reflective surface results in a greater force exerted on the surface, then it would seem that the only thing that can change is the light's frequency. If solar pressure were causing the object to move away from the light source, then the frequency would change by default (Doppler effect).

This almost has to be the answer to what I was asking (how do you account for the motion of the object), but was asking for confirmation that this was what 'balanced' the equation.
 
  • #82
Two gods have bats made made of pure mirrorium. The pitcher throws photons at constant c, but each gods swings their bats at different speeds.

The photon enters the mirror with a speed based upon the perspective of it's last source, but this same photon does not leave the mirror it entered. You're all saying another photon leaves. This photon is manifested in the new reflection source and leaves at a rate based upon where it manifested. It follows Newtons laws launching forth from it's new source, forgeting it's previous launch conditions.

It sounds correct to say light's speed is constant, but it's constant from a source which means lights speed is determined by a combination of the source where it's manifested and the properties of light itself.

If a light is reflected, the source where reflection occurs can increase the lights velocity to a orginating source faster than light left the source originally, just by the newly reflecting source simply accelerating during the reflection process in the direction toward the previous source.

Correct or incorrect?
 
  • #83
omin said:
Two gods have bats made made of pure mirrorium. The pitcher throws photons at constant c, but each gods swings their bats at different speeds.

The photon enters the mirror with a speed based upon the perspective of it's last source, but this same photon does not leave the mirror it entered. You're all saying another photon leaves. This photon is manifested in the new reflection source and leaves at a rate based upon where it manifested. It follows Newtons laws launching forth from it's new source, forgeting it's previous launch conditions.

It sounds correct to say light's speed is constant, but it's constant from a source which means lights speed is determined by a combination of the source where it's manifested and the properties of light itself.

If a light is reflected, the source where reflection occurs can increase the lights velocity to a orginating source faster than light left the source originally, just by the newly reflecting source simply accelerating during the reflection process in the direction toward the previous source.

Correct or incorrect?

Incorrect. Each photon leaves the bat at the speed of light. Since the bat is moving the same direction as the photon, each photon is closer together. In other words, the frequency increases, not the speed.

Edit: Wow! This was the original question. The discussion became so sidetracked I almost forgot there was an original question.

The bat receives photons at a certain rate. It emits the photons at the same rate it received them. But, since the bat is moving, the photons are emitted closer together. That means another observer receiving the photons from the bat will receive them at a higher rate than the bat actually emitted them.
 
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  • #84
BobG said:
The bat receives photons at a certain rate. It emits the photons at the same rate it received them. But, since the bat is moving, the photons are emitted closer together. That means another observer receiving the photons from the bat will receive them at a higher rate than the bat actually emitted them.

The pitcher now has to simultaneously pitch to two gods. Both gods step up to bat. The gods are exactly 60 feet from the pitcher. The pitcher winds up, then throws two photons. Both photons travel c toward both gods. One god is slightly distracted for a moment, but begins his swing just after the other god. The late swinging god compensates by accelerating his bat and in doing so hits the photon harder with his bat. One more thing, both bats hit their photons at the same time.

Do the photons absorb into each bat at the same rate? Does the new photon manifestation process occur at the same rate in each bat? Does each photon emerge from the bat at the same speed, relative to the playing field?

If photon absorbtion and manifestation is simultaneous, and emergece of photons from the bat have the same speed, where does the extra energy go that the late swing god exerted in his swing?

Speed c is determined by the source or what?

If the photon is unaffected by the instataneous intertia of the bat during it's emergence from the bat, then its speed c of emergence is relative to what?

If the photon is affected by the instantaneous inertia of the bat (it's physical origin now), then it should move speed c from the instantaneous inertia of the bat, right?

If the later is true, then late swinging god's photon is now moving faster than the other photon.
 
  • #85
Since the late swinging god's bat is moving faster, they could only hit one photon each at the exact same time. Both would receive the photon at the speed of light - both would send the photon skyward at the same rate.

However, light consists of many photons. It has a wavelength (in fact, that's what distinguishes color). The late swinging, fast swinging god will receive photons at a faster rate than the early swining, slow swinging god. Both will emit photons at the same rate they were received (each photon emitted at the speed of light). Each bat moves between emission of a photon, so even though the photons are emitted at the same rate (frequency) and speed they were received, the photons are emitted closer together.

Players in the field will receive the fast swinging gods photons at a faster rate (frequency) than the slow swinging god, since there was less distance between the photons emitted by the fast swinging gods. Each photon is traveling at the speed of light.

Energy depends upon how many photons each batter is emitting at a time (intensity) and the rate they are emitting the photon packets (frequency). So the difference in energy between the fast swinging god and the slow swinging god is reflected by the rate the players are receiving the photons.

In other words, the energy of the swing is reflected by how many photons are received over a given amount of time, not the speed of each photon.
 
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  • #86
if it's just one photon, energy of the swing makes no difference.

photons have no mass to be accelerated in this fashion
 
  • #87
BobG said:
Since the late swinging god's bat is moving faster, they could only hit one photon each at the exact same time. Both would receive the photon at the speed of light - both would send the photon skyward at the same rate.

Hey Bob, you answered, thank you, but could you explain, because it's not common wisdom to those trying to understand, which is often the only effect of pat answers. This is the question you answered:

Omin said:
Does each photon emerge from the bat at the same speed, relative to the playing field?

An explanation I'm sure would answers these questions:

Omin said:
Do the photons absorb into each bat at the same rate? Does the new photon manifestation process occur at the same rate in each bat?

If photon absorbtion and manifestation is simultaneous, and emergece of photons from the bat have the same speed, where does the extra energy go that the late swing god exerted in his swing?

Speed c is determined by the source or what?

If the photon is unaffected by the instataneous intertia of the bat during it's emergence from the bat, then its speed c of emergence is relative to what?

If the photon is affected by the instantaneous inertia of the bat (it's physical origin now), then it should move speed c from the instantaneous inertia of the bat, right?
 
  • #88
terrabyte said:
if it's just one photon, energy of the swing makes no difference.

photons have no mass to be accelerated in this fashion

All things with physical properties can have action and reaction. (Newton Law III)

Photons do have action and reaction because the full process involved in human vision consciousness directly reacts to photons, which means humans sense photons.(Empiricism)

Only things with physical properties can be sensed, which is only directly by humans or human aided sense, instruments. All things with physical properties have the property of mass. (Empiricism, Technology, The Physical Property of Mass and NL III)

Therefore, photons have the property mass.

If photons don't have mass, then should I throw out Newtons Laws? Newtons laws seem to me to imply mass to anything sensed. Or what?
 
  • #89
omin said:
If photons don't have mass, then should I throw out Newtons Laws? Newtons laws seem to me to imply mass to anything sensed. Or what?
Newton's laws have well known limitations and that's one of them.
Only things with physical properties can be sensed, which is only directly by humans or human aided sense, instruments. All things with physical properties have the property of mass. (Empiricism, Technology, The Physical Property of Mass and NL III)
Since when? That's an assumption based on a narrow-minded view.

All waves, by definition, have no mass.

omin, you asked a lot of questions about C in previous posts. Have you read what Special Relativity has to say about it? It's the second postulate you should be concerned with.
 
  • #90
russ_watters said:
Newton's laws have well known limitations and that's one of them. Since when? That's an assumption based on a narrow-minded view.

All waves, by definition, have no mass.

omin, you asked a lot of questions about C in previous posts. Have you read what Special Relativity has to say about it? It's the second postulate you should be concerned with.

Waves are psychologial theories, which are physically subjective as we speak. I insist they only become thoughts (theory in the mind), because they have a physically properties of a objective origin, unless wave theory has nothing to do with the physical world and is pure fantasy of the imaginative human subjective realm. Any valid theory derives from physics. Is wave theory valid, then? If so, are you saying wave theory is a figment of the mind only and represents only subjective fantastic order? If not, I momentarily put words in your mouth. I apologize on that point. The book Wu Li Masters claims physically objective originating cause of the subjective wave theory through descriptions of past experiments.

I've read the second postulate, but the explanations in my text and in the video I watched represent things in a way that is outside my understanding. That is why I am questioning for explanation. I could give you the pat answers the texts and video asserted, but that doesn't mean I understand. Understanding it is what I am after, not memorization.

Furthermore, narrow minded? I'm open for explanations, how is that narrow minded. I never asserted anything that asserts I am right and everything beyond that is wrong.

Come on man.
 
  • #91
omin said:
Waves are psychologial theories, which are physically subjective as we speak.

No, waves are propagating disturbances in a physical field.

The book Wu Li Masters claims physically objective originating cause of the subjective wave theory through descriptions of past experiments.

The book Quantum Mechanics by Sakurai claims that all physical phenomena are really wave phenomena. Does that mean that the objective world doesn't exist?

You're talking philosophy here, when everyone else in the joint is talking physics.

And you're wrong about photons not having "reactions". When an atom emits a photon, the atom recoils. This happens despite the fact that the photon has no mass.
 
  • #92
russ_watters said:
All waves, by definition, have no mass.

Matter waves have mass.
 
  • #93
Interesting. We sense the atom recoil. Do atoms recoil between photons emiting or just when photons emit? If they only emit when the photon leaves, the photon is involved in the recoil.

The state of the atoms interia (in respect to another atom in non-uniform motion) does not determine the photons speed, but the photon emission process determines the recoil? This appears to represent a violation of N III Law.

The velocity of the body which the atom resides and the velocity of the atom in the body does not determine the photons speed from the atom? If this represents the physics, then the photon moves constant at c across something like the field aether rather and the photon's speed being determined by the atom from which it was emitted.

If the atom does determine the photons c from it, the photon moves specificaly from the atom at c. If another body of atoms were moving slower than this body (in relation to a third point) that simultaneously emitted a photon, the body of atoms traveling faster will emit a photon that travels faster than the slower moving body of atom's emitted photon.

This implies light travels at same speed from atoms through space, but approaches objects in non-linear motion at different speeds.

Or what? I'm open to understand.
 
  • #94
Tom Mattson said:
Matter waves have mass.
You mean like sound (or maybe I don't know what a "matter wave" is...)? Sound waves ride on air, which has mass - sound waves themselves do not.
 
  • #95
You lost me there, Tom. Waves, by definition, have no mass, just mass potential.
 
  • #96
Tom Mattson said:
Matter waves have mass.
A matter wave is more of a verb than a noun. It is not a thing but rather something which describes a thing. The term matter wave usually refers to the wavelike characteristics of the probability distribution associated with a particle which has a non-zero proper mass. I spose that it can apply to a photon to since all the wavelike properties of a photon are identical to the wavelike properties of any other particle and as such they don't depend ont he particle's proper mass.

Pete
 
  • #97
omin said:
Interesting. We sense the atom recoil. Do atoms recoil between photons emiting or just when photons emit? If they only emit when the photon leaves, the photon is involved in the recoil.
For simplicity consider a single isolated atom in an inertial frame of reference. In this frame the atom emits a photon. The atom recoils because the photons are emited. This can be described by saying that in order for the total momentum of the system to be conserved the atom must have momentum and that means it must move. The amount of energy the photon has is directly related to the final speed of the atom. The higher the photon energy the higher the final speed of the atom. If the atom is in a body then, for the purposes of analyzing the dynamics, you can simply consider the body to be that which emits the photon.

No matter what the final speed of the atom, the final speed of the photon is always the same, c. All that is different for photons with different momentum is the energy of the photon. The speed of the atom, however, is a function of the atoms final proper mass (the proper mass of the atom must have decreased in this process) and the atom's momentum.

Pete
 
  • #98
omin said:
Interesting. We sense the atom recoil.

I'm pretty sure that no one has ever "senses" an atom recoil.

Do atoms recoil between photons emiting or just when photons emit? If they only emit when the photon leaves, the photon is involved in the recoil.

They recoil as a direct result of emission (or absorption, for that matter) of photons. This is because the photon carries momentum and energy, and both are conserved quantities.

The state of the atoms interia (in respect to another atom in non-uniform motion) does not determine the photons speed, but the photon emission process determines the recoil? This appears to represent a violation of N III Law.

It doesn't violate Newton's third at all. In fact, it's entirely consistent with it. The change in momentum of the atom is precisely equal to the momentum of the photon.

The velocity of the body which the atom resides and the velocity of the atom in the body does not determine the photons speed from the atom?

No. The speed of the photon is c, regardless of the motion of the atom.
 
  • #99
Matter waves

russ_watters said:
You mean like sound (or maybe I don't know what a "matter wave" is...)? Sound waves ride on air, which has mass - sound waves themselves do not.

Chronos said:
You lost me there, Tom. Waves, by definition, have no mass, just mass potential.

What does QM teach us? It teaches us that particles act as waves. These waves are referred to as matter waves.

pmb_phy said:
A matter wave is more of a verb than a noun. It is not a thing but rather something which describes a thing. The term matter wave usually refers to the wavelike characteristics of the probability distribution associated with a particle which has a non-zero proper mass.

I don't see how "matter wave" can be considered a verb. For instance, an electron is a matter wave. It doesn't do a matter wave.

I spose that it can apply to a photon to since all the wavelike properties of a photon are identical to the wavelike properties of any other particle and

Not really. As I'm sure you know, the wavelike properties of light are described by the EM wave equation. Not so with matter waves. If we want to get relativistic, then spin-0 bosons are described by the Klein-Gordon equation, and spin-1/2 fermions are described by the Dirac equation. There are more complicated equations for higher spins, but none of them is identical to the EM wave equation.

as such they don't depend ont he particle's proper mass.

Would you consider frequency and wavelength "wavelike properties"? If so, then the wavelike properties of matter waves depend on their proper mass.
 
  • #100
They recoil as a direct result of emission (or absorption, for that matter) of photons. This is because the photon carries momentum and energy, and both are conserved quantities.

So this explains the (1+q) part of this equation?

[tex]F=\frac{F_sA}{cm}(1+q)cosi[/tex]

In other words, all the photons received are received and some force is exerted to the surface receiving them.

Depending upon the reflectivity of the surface, only a certain percentage of the photons are emitted and only the departing photons affect the momentum of the surface.

The difference, the absorbed photons, have their kinetic energy converted to potential energy by raising the level of the electron's orbit.

Fairly close?
 
  • #101
BobG said:
So this explains the (1+q) part of this equation?

[tex]F=\frac{F_sA}{cm}(1+q)cosi[/tex]

I'm not familiar with the equation. What do all the variables stand for?
 
  • #102
BobG said:
[tex]F=\frac{F_sA}{cm}(1+q)cosi[/tex]
where [tex]F_s[/tex] is solar pressure or 1367 W/m^2.
c is speed of light
m is mass of satellite
q is reflectivity (1 for totally reflective, 0 for totally absorbant)
i is incidence angle

The equation refers to the affect of solar pressure on high altitude satellites. Over time, it causes torques to build up on the spacecraft that have to be compensated for to keep the satellite's sensors/antennas/etc pointed accurately. It also affects the shape of the orbit, since solar pressure slows the satellite slightly when the satellite is headed towards the sun and speeds it up slightly when it is headed away from the sun.
 
  • #103
pmb_phy said:
...The atom recoils because the photons are emited...for the total momentum of the system to be conserved the atom must have momentum... The amount of energy the photon has is directly related to the final speed of the atom...No matter what the final speed of the atom, the final speed of the photon is always the same, c. All that is different for photons with different momentum is the energy of the photon.

The change in velocity of atom (in recoil) is directly proportional to the amount of energy of the photon, but the photon's velocity isn't? How is that consistent with conservation of energy? In every physical collision, the velocity change of one entity is directly proportional to the change of velocity of the other entity, unless the quantity of change of velocity is internalized in the photon, making it unapparent to the viewer. Is this what the photon does?

Tom Mattson said:
I'm pretty sure that no one has ever "senses" an atom recoil.

Couldn't this be done through instrument aided sense?
 
  • #104
omin said:
The change in velocity of atom (in recoil) is directly proportional to the amount of energy of the photon,

Where are you getting this from?

First, the change in velocity is a vector, and the energy of a photon is not. There is no way that one could be proportional to the other. Second, even if we were talking about the change in the speed of the atom, this wouldn't be right. The change in speed of the atom is determined by:

(1/2)matom(vf2-vi2)=ΔEphoton.

That's not a direct proportion!

but the photon's velocity isn't?

Right. The photon's energy is directly proportional to its frequency.

Couldn't this be done through instrument aided sense?

Either the human senses it, or the instrument does. I stand by my original statement: humans don't sense atomic recoil. It's below the threshold of our sense of touch.
 
  • #105
Well, I'm probably mixing apples and oranges, but it kind of feels like all the atoms in my skin are moving faster when I step into the sunlight.

This is a complicated subject when you try to figure out its relationship to things you observe.

You're receiving light. Some of the light is reflected. Some of the light exerts a force that can move objects (the same light that is reflected). Some of the light creates heat (the portion that isn't reflected). It almost does seem like we're getting too much energy out of the transaction.
 

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