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Exactly.newjerseyrunner said:Why would you define white as all visible colors but define black as no colors at all? I would define black as no visible colors and colorless to mean no light at all.
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Exactly.newjerseyrunner said:Why would you define white as all visible colors but define black as no colors at all? I would define black as no visible colors and colorless to mean no light at all.
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Yes I like it! Another obscure clarification would be that it is NOT "invisible" as in see-thru or cloaked, it's colorless which is blacker than any black around it...newjerseyrunner said:Black - no wavelengths between 390 and 700nm
Colorless - no wavelengths at in any part of the spectrum
Is that 4 "balls" makes a "walk" and if there is a person on first base they walk to second and so on? I am not a big sports fan but I think I remember the rules from my youth. I'm not sure what you mean by 2 bases? Is that just saying you're going to teach a different "interpretation", if you will pardon the poor analogy, where you describe going from home to first as "two bases"?Vanadium 50 said:Would you start teaching baseball by explaining that it's not really one base on an overthrow, it's actually two bases? (The base the runner is going to, plus one)
Really I was going to say white would be all wavelengths from not quite infinite all the way to up to God knows where but I knew that would be over-dramatic and besides the point at hand...newjerseyrunner said:Why would you define white as all visible colors but define black as no colors at all? I would define black as no visible colors and colorless to mean no light at all.
Sally never sees Bob getting beyond the EH. Bob falls all right onto the BH, just that Sally never sees it.Chronos said:Remember Bob, Sally and the black hole? Bob volunteers[?] to cross the event horizon while Sally stays on the ship and watches. Bob never makes it, Sally watches as Bob slows to a halt and freezes upon reaching the EH due to time dilation. So, how can a black hole form when infalling matter takes an eternity to cross the EH?
He is talking about an overthrow. Say a ball is grounded to the Shortstop, and he makes a quick but wild throw into the stands. The throw would ordinarily have resulted in the runner out at first base, as the runner was moving between home-plate and 1st base. The runner cannot just run around the bases and score, and the 1st baseman cannot go into the stands and retrieve the ball, and throw to second base. The rule says runner gets 1st base, and then second. 1st base, because they did not throw him out there, and 2nd because otherwise, he is free to keep going, until the other team retrieved the ball and tagged him out, or he scored. The rule stops play with the ball going into the stands, and the runner gets the base he was going to, plus 1 more. Other runners on the base path also get a bonus base ... so a base-runner from 2nd running to 3rd would get awarded 3rd and home when the throw went into the stands at 1st base.jerromyjon said:Is that 4 "balls" makes a "walk" and if there is a person on first base they walk to second and so on? I am not a big sports fan but I think I remember the rules from my youth. I'm not sure what you mean by 2 bases? Is that just saying you're going to teach a different "interpretation", if you will pardon the poor analogy, where you describe going from home to first as "two bases"?
I disagree. There has been 10year (or so) project that mapped the trajectories of the stars right at the center of the Milky Way and they show the existence of an object so massive and so small that it can't be anything but a black hole, so I don't think the recent LIGO results were the first strong evidence.votingmachine said:How about the basic misconception of the existence of black holes at all? The recent gravity wave discovery shows two very large masses colliding, and from what I gather, is the first truly strong evidence that black holes definitively exist.
I'm not able to disagree. The main reason I raised it was I read that the LIGO results were important confirmation. I know of some other measured things that also are considered strong support of the existence of black holes. If I had not read that around the LIGO results, I would have regarded black holes as proven with a great deal of certainty. It could easily be that the story I read exaggerated the current lack of evidence ... and I clearly have not gone looking to see all the supporting evidence. A reporter might easily report that LIGO was the first really strong confirmation of a theory other than gravity waves. Observational confirmation of one theory might be mistaken for another.phinds said:I disagree. There has been 10year (or so) project that mapped the trajectories of the stars right at the center of the Milky Way and they show the existence of an object so massive and so small that it can't be anything but a black hole, so I don't think the recent LIGO results were the first strong evidence.
EDIT: I DO agree that the existence of BH's has been called into question, right from when they were first proposed as real objects (Einstein thought they were a mathematical fiction, as I recall).
I'm just trying to retract what I said without sounding like an idiot ... but never mind what I sound like .. really, it was nothing the OP should be running with.nikkkom said:"Unambiguous" is subjective.
There are people who don't believe that stars are powered by fusion... (the "electric universe" crowd)
As Hawking himself has said, this whole business of "virtual particles" causing Hawking radiation is not correct. It was just the only way he could find to describe in English something that really can only be described in the math, so your statement here is based on an incorrect premise and therefore is not anything you need to be concerned about.MikeL# said:...
2. But when describing evaporation of black holes (e.g. paragraph 2 and 3 of https://en.wikipedia.org/wiki/Hawking_radiation#Overview ), 'virtual' matter [e.g. electron] and corresponding anti-matter [positron] are created out of 'the vaccuum' at event horizon. If the electron is ejected, then the positron is absorbed into the black hole which loses mass. In this case the positron mass is negative. (But if the electron were absorbed then the black hole would gain mass - so I have misunderstandood something here.)
"anti matter" has positive mass and is gravitationally attracted to normal matter just as normal matter is. The "anti-" just means it has some other quantum characteristic that is the opposite of normal matter. For example, positrons have a positive charge instead of the negative charge of electrons but that has nothing to do with mass.MikeL# said:Thanks phinds for clearing that up - so I can tell the friend who asks me:
1. Real anti-matter (like positrons) definitely has positive mass/energy and not negative.
2. Black holes do not suggest anti-matter has negative mass - that would be misinterpreting QFT etc.
Kinda looks like a simple radial blur photoshop filter1oldman2 said:Just wondering what everyone makes of this?
Sure does. Also, the area around it (outside the blurred area) seems too uniformly distributed.Greg Bernhardt said:Kinda looks like a simple radial blur photoshop filter
Funny but the "shop effect" was my first thought also. I thought I'd throw it on the table for discussion since it's from NASA and not just another You tube crackpot deal.phinds said:Sure does. Also, the area around it (outside the blurred area) seems too uniformly distributed.
1oldman2 said:Just wondering what everyone makes of this?
http://www.nasa.gov/image-feature/computer-simulated-image-of-a-supermassive-black-hole
View attachment 99129
I believe its meant to be more a representation of an area rather than an actual object. I have to concede nearly complete ignorance of the subject myself, I am able to learn a lot however by posting a question (#51 would be an example) and following the comments on the thread.Flyx said:I'm not sure about the black circle in the middle? Wouldn't gravitational lensing make it not possible to actually 'see' the black hole?
PAllen said:That image seems correct and consistent with other calculations (the background assumed is presumably overly uniform to simplify the calculation). For example, here is a simulation by one the largest, most reputable, numerical relativity groups:
You are finding the density as if the mass were spread out throughout the region inside the event horizon. But general relativity says that the mass will not be so spread out-- everything inside the EH must fall to the center. We have no theory to say what the density at the center would be, if we do not believe it would be what GR says (infinite).Gregoriorosso said:I am surprised by many statements about bh - let’s take density.
In my normal life, it is defined as ρ = mass/volume
but what’s the volume of a bh ?
I guess
4/3 π R^3 ?
as R = is 2GM/c^2 it seems to me that ρ = 3c^6/32πGM^2
A bh with 10^9 solar masses (that is a large one, but not the largest)
has ρ = 8,15E-20 kg/cubic meter = the density of a good vacuum with 50 millions of hydrogen atoms / cubic meter.
Hundred times the density of the interstellar space.
ProfuselyQuarky said:Rather, black holes are extremely dense with matter, which causes them to have such a massive gravitational force.
Intresting said:Well it has been proven that a particle can be at two places at once.
The quantum superposition theory doesn't necessarily state that a particle can be in two places at once, the theory goes as far as to say that a particle can be in an infinite number of positions or any given point at any given time. There is no proof of this though. Only experiments that seem to provide evidence, still theory.Intresting said:Well it has been proven that a particle can be at two places at once. Link for reference http://www.reuters.com/article/us-nobel-physics-quantum-idUSBRE8980V620121009
They told me that the density of water is approximately 1 kg/liter. That was long time ago, when I didn’t know the density of the atomic nuclei of oxygen or hydrogen. Some years later I was informed that the density of water is much lower than the density of atomic nuclei, but the density of water at STP (should I add standard terrestrial space-time ?) is still 1 kg/liter.Ken G said:You are finding the density as if the mass were spread out throughout the region inside the event horizon. But general relativity says that the mass will not be so spread out-- everything inside the EH must fall to the center. We have no theory to say what the density at the center would be, if we do not believe it would be what GR says (infinite).
Per classical GR, the event horizon has exactly zero density for a BH more than a millisecond old, and soon the near central density approaches infinite. Of the hypothetical quantum gravity approaches, none that I know of posits any unusually high density at or near the horizon. For example, the firewall hypothesis has high temperature at the horizon, not high density. Generally, what these post GR theories propose is that you have 'near vacuum' outside some ball of finite radius (which may be inside or approximately at the horizon). What the density (gradient) of this ball is, is not well predicted by these (unverified) theories.Droidriven said:It isn't their density that gives them their massive gravity, it is their mass, they can be any size(in theory) but they are not as dense as commonly believed, immense density is another misconception. There "may" be areas such as the EH or the proposed singularity that are extremely dense but that density is not consistent through the entire mass. Regions of density with emptiness between the dense regions.