What is the current through resistor 2 in a series circuit?

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In a series circuit with three resistors of 3.0 ohms each powered by a 3.0 V battery, the current through each resistor is calculated using Ohm's law. The total resistance is 9.0 ohms, not 3.0 ohms, leading to a current of 0.33 A. It is emphasized that current is measured in Amps, not Ohms. Participants confirm that the current remains the same through all resistors in a series circuit. The user is advised to create a new thread for additional questions or continue asking in the current thread.
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Homework Statement


First problem is a series circuit with 3 resistors. R1,R2,R3 is 3.0 ohms. This is all powered by a 3.0 V battery.

What is the current threw resistor 2?


Homework Equations


V=IR


The Attempt at a Solution



3.0=I(3.0)

Divide both sides by 3.0 and I got 1
.. the correct answer is 0.33 OHMs
 
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First of all, the units of current are Amps. I also believe that you misread the question. The total resistance is not 3ohms, instead EACH resistor has a resistance of 3 ohms. So you need to find the equivalent series resistance first, and then apply ohm's law and get the correct answer of 0.33A.
 
erm. . . check your solutions, current is not measured in Ohms.

First, find equivalent resistance, and remember that current thru a series of resistors is the same.
 
Ok I got the right answer. I got the total resistance and divide it by the volts and i got the current. Thanks guys! What if I have another question on this same sort of problem do i make another thread? Or should i just ask here?
 

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