Why don't heavy objects fall more SLOWLY?

[Buckleymanor]

No, the engines are only exerting a force on the ship, not the ball. The ship is not more massive because the ball is there. Only once the ball reaches the other side of the ship will it's mass have to be taken into account in regards to the acceleration.

From the moment the ship takes off it will expend more fuel and accelerate less if a heavy object is on board if this was not the case you could take a mountain on board and use no more fuel than if a marble was there.
What is mass if it is not the resistence to a force applied.

 

[Drakkith]

From the moment the ship takes off it will expend more fuel and accelerate less if a heavy object is on board if this was not the case you could take a mountain on board and use no more fuel than if a marble was there.
What is mass if it is not the resistence to a force applied.

Ignore the ship taking off. Focus on the deceleration part. That is where your confusion lies. If the ball is NOT in contact with the ship then the ship cannot exert a force upon it, meaning that it takes no extra energy to decelerate the ship while the ball is not in contact with the ship.

 

[Buckleymanor]

Ignore the ship taking off. Focus on the deceleration part. That is where your confusion lies. If the ball is NOT in contact with the ship then the ship cannot exert a force upon it, meaning that it takes no extra energy to decelerate the ship while the ball is not in contact with the ship.

I agree it won't exert a force on the ball if it is not in contact with it but it will still have to use more energy to decelerate a faster moveing ship, and that depends on which ball was on board when it was first accelerating.

 

[Drakkith]

I agree it won't exert a force on the ball if it is not in contact with it but it will still have to use more energy to decelerate a faster moveing ship, and that depends on which ball was on board when it was first accelerating.

We are not decelerating to a stop, we are only decelerating until the ball hits the opposite wall. The ship will not take more time to decelerate for either one.

 

[TurtleMeister]

I agree it won't exert a force on the ball if it is not in contact with it but it will still have to use more energy to decelerate a faster moveing ship, and that depends on which ball was on board when it was first accelerating.

It appears that your misconception is that the speed relative to the point of take off is relavent to this time interval. Well, it is not. The time interval in question remains the same regardless of what speed the spacecraft has attained relative to the start point and regardless of how much energy it took to achieve that speed.

 

[Jasso]

I agree it won't exert a force on the ball if it is not in contact with it but it will still have to use more energy to decelerate a faster moveing ship, and that depends on which ball was on board when it was first accelerating.

$$F = ma$$
The accelration only depends on the total force applied and on the mass that is being accelerated. Since there is no force on the ball when not in contact, it will not be accelerated, so the only thing being accelerated is the ship. Since the only thing being accelerated is the ship and the thrusters have the same force in both cases, it will have the same acceleration in both cases until the ball hits the other side.

 

[Buckleymanor]

It appears that your misconception is that the speed relative to the point of take off is relavent to this time interval. Well, it is not. The time interval in question remains the same regardless of what speed the spacecraft has attained relative to the start point and regardless of how much energy it took to achieve that speed.

So for a spaceship traveling at allmost lightspeed the time intervall will be the same as craft traveling at 1000Kph.

 

[Whovian]

So for a spaceship traveling at allmost lightspeed the time intervall will be the same as craft traveling at 1000Kph.

I think we're talking in the reference frame of the ship(?), in which case it won't matter what velocity it is traveling at relative to the takeoff point. The ship observes the takeoff point as time dilated and length contracted, the takeoff point observes the ship as time dilated and length contracted.

 

[TurtleMeister]

So for a spaceship traveling at allmost lightspeed the time intervall will be the same as craft traveling at 1000Kph.

Yes, that is correct (in the reference frame of the spacecraft ).