Spring Definition and 999 Threads

Hi. I have a application for a bistable spring mechanism. But my problem is that all of the ones i have seen require to go past the "midpoint" before it flips to the other side. Is there any such mechanism that flips over to position 2 before you get to the "midpoint" from position 1? Example...

Summary:: Calculating the inclination angle A stick is on two springs with spring constants D1=500N/m and D2=300N/m. Consider the stick is without mass and can rotate around the point E, which is distant from spring 1 with 0,1m and from spring 2 with 0,8m. A force F=100N pulls the stick up...

1/2 m v2 + mgh = 1/2 k x2 1/2 (5) (9) + (5) (9.81) x = 1/2 (200) x2 100 x2 - 49.05 x - 22.5 = 0 x = 0.779 m or x = - 0.289 m Answer key says the answer is 0.289 m but in my opinion the answer should be 0.799 m because I take h = 0 at the position where the spring has maximum compression so...

Hi, Could I please ask where I am going wrong with this very simple question: Here's my answer (units implied): A force of 20 extends the spring by 1/100 and so the Work Done in performing this extension is 20 * 1/100 = 1/ 5 Now, the work done in extending a spring is given by the formula...

T = 2π * √(2/300), T = .513 seconds. If I divide it by 4/3, I get a final answer of .385 seconds of touch. I know the box isn't attached for the entire oscillation, so T has to be divided. To me, it makes sense to divide it by 4/3 (when the box falls, the spring is compressed, hits...

Here's a picture of what I tried. I was wondering if this is correct?

Equations provided: for a spring pendulum and m replaced with L and k with g for the same pendulum, but with no weight attached. Greetings I tried solving this by stating that the length is 0,50m (since no length of the spring is given) and turning around the equation for the spring...

Why doesn't the incline angle play a role in changing the ##m## component of this equation? ##T = 2π\sqrt{\frac{m}{k}}## FOR QUESTION 25, PART B: ANSWER:

My Solution: For the displacement graph, the gradient is crucial to predict the behaviour of the displacement of the block through time. At 1: System is released - velocity is zero, considering forces acting on block, kx < mg, as block is observed to move downwards, and object is...

I'm all messed up on this problem. I see you can get the solution (74cm, as listed in the back of the book) by simply setting mgh=1/2kx^2, saying that h=x, and then adding 15 cm to that since that's the original length of the spring. This is the solved solution I was given. But now I think...

From what I understand, the force between two current-carrying wires can be calculated as: $$\dfrac {F}{L}=\dfrac {\mu _{0}I_{1}I_{2}}{2\pi R} $$ Doesn't this mean: $$\dfrac {F}{L}=\dfrac {\mu _{0}I_{1}I_{2}}{2\pi 1^{2}}=\dfrac {1}{2}kx^{2} $$ ? $$\dfrac {\left( 4\pi \times 10^{-7}\right)...

Its a very basic problem and my friend suggested a solution that we should equate mg and kx ie mg=kx and just plug in m=8 and x=0.16 but i think that we should equate the energies like mgx=1/2kx^2 ie because at the point where mg will be equal to kx the mass will still have a velocity hence it...

Could I please ask for help regarding part (a) of this question: If I get part (a) then part (b) will follow. So, here's my answer to part (a): I'll be using the formula Elastic Potential Energy in a spring = (Yx^2)/(2a) Where Y is the modulus of the spring, x the extension and a the natural...

a) Our force can be represented as: $$\vec F= -k(r-H) \hat r$$ then the equations of motion are: $$\hat r: \ddot r -r {\dot{\theta}}^2=-\frac{k}{m_1}(r-H)$$ $$\hat{\theta}: r \ddot{\theta} + 2 \dot r \dot{\theta}=0$$ Plus we know that angular momentum is constant then $$|\vec L|=m r^2...

My solutions: When ball is launched horizontally, assuming its velocity is entirely in the horizontal dimension, there is no interaction of the ball with the gravitational field, thus no change in GPE, so all of the EPE (elastic potential energy ) of the spring is transferred to KE of the ball...

Hello All. I am mentoring a high school student in my area with his class project for school. He has chosen he wants to launch an object (in our case, a softball) into a 5' diameter area. The idea is to build basically an oversized slingshot using an extension spring as the source of energy. We...

Hello! I am stuck on part of a problem and was wondering what I am doing wrong. For part a of the problem, we were asked to find the impact speed. I did this in a photo below given the following values: Θ = 30 degrees. The initial velocity = 10 m/s. The coefficient of kinetic friction = 0.4...

Hi everyone, just a quick question.. I tried this problem using Newtons laws, not conservation of energy, and I got an answer exactly half of what the correct answer is, and I'm not sure why. Here is what I did: Net force = zero once the spring is compressed, therefore mg - kx = 0 mg = kx...

Okay so, recently I got a job with my local newspaper delivering newspapers to make some money while deciding how I want to continue my educational career (I already have some college under my belt but I'm taking a semester off). All the newspapers have to be at the houses by 6 am so in order to...

Consider a spring with one end attached to a wall and the other to a free mass, which is then stretched so some potential energy U. After it has been released and has de-stretched, the change of elastic potential energy is -U which equates to the negative of the work done by the spring force on...

I wrote Newton's equations for the block seen from the non inertial frame. The axis are inclined. ##x) Fe+W_x-f*cos(\alpha)=0## ##y) N-f*sin(\alpha)-W_y=0## Where ##f*## is the pseudo-force and ##Fe## is the elastic force. I set the acceleration as 0 because they are in equilibrium. The thing...

I've solved all the cases in the non inertial system. A) For ##m_1## we have ##x) P_{1x} -T=m.a_x## ##y) N_1 -P_{1y}=m.a_y## For ##m_2## we have ##y) T+F_e -P_2=m.a_y## As it moves with constant velocity I solve it setting ##a_x=0##. So for ##m_1## ##mgsin(\alpha)=T##, then I replace it in...

Do you have any information's about how to calculate the bias spring or the Force needed ? the current necessary to heat the SMA spring for a 4mm stroke ? Thank you

This is a fun one, sort of! I am working on a singing saw that can be amplified with a regular magnetic pick up, from an electric guitar. I made a blade from laser cut1095 blue tempered spring steel (0.042" thick). It sounded great, but after a few months of service, the blade cracked. What is a...

Homework Statement: A box of mass M=30 kg sits on a ramp which is tilted at angle 13 degrees. The coefficients of static and kinetic friction between the box and the ramp are both 0.12. The box is connected to a spring of spring constant k=9 Newtons per meter. Initially, the box is held in...

I have a spring which I am using to cushion a simple device, but it has proven to be too stiff for the purpose. Is there a way to reduce the stiffness of a spring, without making it brittle or malleable? I have access to ovens which can achieve 550°C, which can also quench in water or poly-oil...

I encountered a weird conflict between my thought process and that of author's solution in book: The common viewpoint of both of us were invoking conservation of energy of this SHM system But the author proceeds to solve it using conservation of momentum, taking the new mass added to system as...

If I take the vector sum, I am getting the angle to be 1. (tan^-1 tan(1)). Is that correct?

Hola! So my first approach to this is use both the conservation of energy and momentum equations since collision between the first two objects are elastic. Let the 3 blocks be a,b and c (from left to right) Does this means the following: whereby ##v_{a} ##= speed of block a after collision...

Hi all. Multiple part problem that I'm really stuck on. I'll attach a file. At first I had attempted the whole problem with the idea that fixed wall was a fixed point, and that the mass on a spring was a "free" point. But I learned later that the mass can't be treated like a "free" point since...

Classical problems for hookes law generally give either mass or spring constant. What if I have a graph of a wavelike structure that is oscillating which I can use to measure for example: T (period), t (time), Δx (displacement), v (velocity), a (acceleration) and other variables is this...

I figured out that the spring constant is inversely proportional to the natural length, but there’s still an unknown change in a quantity( most likely extension).

How far will the spring extend, given that the block is not attached? Will it extend beyond its natural length? How to calculate at what point the box comes off the spring?

Dear all, I am back with another Spring problem. I have tried to use the insights I gained from your help last time: https://www.physicsforums.com/threads/find-v-x-of-a-mass-suspended-from-a-spring.972942/page-3#post-6190934 I figured I start with calculating the new equilibrium by ## x...

if you drop a spring that is elongated via its only weight (slinky) vs another spring that is on its side... will both hit the ground at the same time?

I was looking at this spring to make a constant torque motor: https://www.ondrives.com/sr119 They come in many sizes and I've been trying to get my head around the specifications so I buy the right one. Take the one I linked above as an example, it's listed as 6.18N (63kg) at the top of...

I was thinking about making a kind of counterbalance weight. So I was looking this spring to make a constant torque motor. https://www.ondrives.com/sr119 They come in many sizes but to take this one as an example it's listed as 6.18N (63kg) at the top of the page. At a glance considering the...

I am struggling through a problem in one of my designs and would appreciate some help. Please refer to the image attached. Problem Description: S = Torsion spring F = fixed point T = tire A tire is attached to a torsion spring through an arm as shown in the image. The torsion spring has one...

Tried to find the resultant force, but I can't see how the magnetic field affects. I used Faraday's law to find the the diferece of potentials in the plate Wich should be B.d.v, where v is the vertical velocity of plate, but there were not given the resistance or resistivity to relate with the...

So we know that all the energy originates from the spring: E(spring) = (1/2)kd^2 As the block moves up the ramp, friction does work on the block over a distance of 2d: W = μmgcos(θ)* 2d So subtracting the work done by friction from the spring energy, gives us the energy left, so we'll set it...

"It should be able to accelerate from rest to 20 m/s at least 50 times before the spring needs winding" -So F = -kd = -k(2.1) - d is 2.1 because it is the compression length Now, since we know the d, divide it by 50, 2.1/50 = 0.042m Basically, the spring unwinds 0.042 m 50 times for a total...

Let's say you have a box and there is a spring attached to it and the other end of the spring is attached to the wall. If you press the box towards the wall the spring presses back against the box with an equal force. F(push) = 20N, F(spring) = -kd. F(push) - F(spring) = F(net). Which is zero...

Problem Statement: A 2.0 kg cart and an 8 kg cart are connected by a relaxed, horizontal spring of spring constant 300 N/m. You pull the 8 kg cart with some constant horizontal force. The separation between the carts increases for a short time interval, then remains constant as you continue to...

Which formula do I have to use? and why?

I was wondering, I have an engine that should keep a spring compressed. How can I calculate the power necessary for this? The work is Force x Distance, as there is no distance, there is no work, so no power... But obviously to keep the spring compressed the engine will have to produce a...

The question asks for a bunch of stuff, but I have everything except part d down. a) Setting the mass of lemons as m1, I used m1*gh = 1/2mv^2, solving for v of the lemons as v = √2gh, where h is the height at which it is dropped. Then, I used COM and had this equation (not 100% sure if right)...

I am really stuck and confused. I just need the equation. Thanks! Here is my attempt at solving: PEspring = 1/2m(Vx^2 +Vy^2)

I am new to Simulink and I wanted to start practicing using a spring mass damper system. My first tutorial was this: Later, I wanted to model a spring system where a mass moving at a known velocity hits the spring. The governing equation and a similar modeling method given in the previous...

Hello, do someone have time to help me out with an assignment? My question In the answer sheet they say: What I do not understand is why m is withdrawn from both sides, since I don't see that those represent the same mass. When I did the assignment I thought m at the left side would be the...

I thought work is 0 because force is applying perpendicular to the spring's moving direction. these pulses are transverse pulse since those have amplitude, and pulse is moving horizontal, which means applying force horizontally, but spring is moving vertical. So my conclusion is "because pulse...